From the diagram above calculate the total curr... - JAMB Physics 2017 Question

From the diagram above, calculate the total current in the circuit

V = IR from ohms law

I = (\frac{V}{R})

Since the resistance are in parallel

(\frac{1}{Reff}) = (\frac{1}{8}) + (\frac{1}{12}) + (\frac{1}{6})

= (\frac{2 + 3 + 6}{36}) = (\frac{11}{36})

Reff = (\frac{36}{11}) = 3.27

I = I₁ + I₂ + I₃

= (\frac{V}{Reff})= (\frac{12}{3.27})

= 3.669A

I = 3.7A